长得有点胖,老被人催着减肥. 下面来看看二叉树有多“胖”,程序如下:
#include<iostream>
#define N 63
using namespace std;
char str[] = "ab#d##c#e##";
int i = -1;
typedef struct node
{
struct node *leftChild;
struct node *rightChild;
char data;
}BiTreeNode, *BiTree;
//生成一个结点
BiTreeNode *createNode(int i)
{
BiTreeNode * q = new BiTreeNode;
q->leftChild = NULL;
q->rightChild = NULL;
q->data = i;
return q;
}
BiTree createBiTree1()
{
BiTreeNode *p[N] = {NULL};
int i;
for(i = 0; i < N; i++)
p[i] = createNode(i + 1);
// 把结点连接成树
for(i = 0; i < N/2; i++)
{
p[i]->leftChild = p[i * 2 + 1];
p[i]->rightChild = p[i * 2 + 2];
}
return p[0];
}
void createBiTree2(BiTree &T)
{
i++;
char c;
if(str[i] && '#' == (c = str[i]))
T = NULL;
else
{
T = new BiTreeNode;
T->data = c;
createBiTree2(T->leftChild);
createBiTree2(T->rightChild);
}
}
int max(int x, int y)
{
return x > y ? x : y;
}
int getDepth(BiTree T)
{
if(NULL == T)
return 0;
return 1 + max(getDepth(T->leftChild), getDepth(T->rightChild));
}
int getNodeAtLevel(BiTree T, int level)
{
//下面的条件可以修正为:if(NULL == T),但最好不要修改
if(NULL == T || level < 1 || level > getDepth(T))
return 0;
if(1 == level)
return 1;
return getNodeAtLevel(T->leftChild, level - 1) + getNodeAtLevel(T->rightChild, level - 1);
}
int getBreadth(BiTree T)
{
if(NULL == T)
return 0;
int breadth = getNodeAtLevel(T, 1);
int depth = getDepth(T);
int i;
for(i = 1; i <= depth; i++)
{
if(breadth < getNodeAtLevel(T, i))
{
breadth = getNodeAtLevel(T, i);
}
}
return breadth;
}
int main()
{
BiTree T1;
T1 = createBiTree1();
cout << getBreadth(T1) << endl;
BiTree T2;
createBiTree2(T2);
cout << getBreadth(T2) << endl;
return 0;
}